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78 lines
3.1 KiB
C++
78 lines
3.1 KiB
C++
#include "float_to_string.h"
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void FloatToString::printBase10IntegerWithDecimalMarker(char * buffer, int bufferLength, int i, int decimalMarkerPosition) {
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/* The decimal marker position is always preceded by a char, thus, it is never
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* in first position. When called by convertFloatToText, the buffer length is
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* always > 0 as we asserted a minimal number of available chars. */
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assert(bufferLength > 0 && decimalMarkerPosition != 0);
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int endChar = bufferLength - 1, startChar = 0;
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int dividend = i, digit = 0, quotien = 0;
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if (i < 0) {
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buffer[startChar++] = '-';
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dividend = -i;
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decimalMarkerPosition += 1;
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}
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/* This loop acts correctly as we asserted the endChar >= 0 and
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* decimalMarkerPosition != 0 */
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do {
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if (endChar == decimalMarkerPosition) {
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buffer[endChar--] = '.';
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}
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quotien = dividend/10;
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digit = dividend - quotien*10;
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buffer[endChar--] = '0'+digit;
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dividend = quotien;
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} while (endChar >= startChar);
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}
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void FloatToString::convertFloatToText(float f, char * buffer, int maxNumberOfChar, Mode mode) {
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/* We here assert that the buffer is long enough to display any float in a
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* understandable way: the worst case has the form -1e-38 (6+1 char). */
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assert(maxNumberOfChar > 6);
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//if (isinf(f)) {
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float maximalFloat = 3.4f*powf(10, 38);
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if (f > maximalFloat || f < -maximalFloat) {
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buffer[0] = 'N';
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buffer[1] = 'a';
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buffer[2] = 'N';
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buffer[3] = 0;
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return;
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}
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float logBase10 = f != 0.0f ? log10f(fabsf(f)) : 0;
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int exponentInBase10 = logBase10;
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if ((int)f == 0 and logBase10 != exponentInBase10) {
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/* For floats < 0, the exponent in base 10 is the inferior integer part of
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* log10(float). We thus decrement the exponent for float < 0 whose exponent
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* is not an integer. */
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exponentInBase10--;
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}
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int numberOfCharExponent = exponentInBase10 != 0 ? log10f(fabsf((float)exponentInBase10)) + 1 : 1;
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if (exponentInBase10 < 0){
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// If the exponent is < 0, we need a additional char for the sign
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numberOfCharExponent++;
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}
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/* Future optimisation, if mode > 0, find the position of decimalMarker and
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* decide whether to display the exponent. */
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// Number of char available for the mantissa
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int availableCharsForMantissa = maxNumberOfChar - numberOfCharExponent - 2;
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// Compute mantissa
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/* The number of digits in an integer is capped because the maximal integer is
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* 2^31 - 1. As our mantissa is an integer, we assert that we stay beyond this
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* threshold during computation. */
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int numberMaximalOfCharsInInteger = log10f(powf(2, 31));
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assert(availableCharsForMantissa < numberMaximalOfCharsInInteger);
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int mantissa = f >= 0 ? f * powf(10, availableCharsForMantissa - exponentInBase10 - 2) : f * powf(10, availableCharsForMantissa - exponentInBase10 - 3);
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// Print sequentially mantissa and exponent
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printBase10IntegerWithDecimalMarker(buffer, availableCharsForMantissa, mantissa, 1);
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buffer[availableCharsForMantissa] = 'e';
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printBase10IntegerWithDecimalMarker(buffer+availableCharsForMantissa+1, numberOfCharExponent, exponentInBase10, -1);
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buffer[availableCharsForMantissa+1+numberOfCharExponent] = 0;
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}
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