Léa Saviot 9d6bab092f [poincare/parser] Identifier is not already function -> symbol ...

We check the context: if an identifier is already a function, we
interpret it as such, otherwise it is a symbol.
This way, in the Equation app, x(x+1) is interpreted as x*(x+1)

2020-02-12 15:13:21 +01:00

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